Question: In the hydroboration - oxidation reaction of propene with diborane, $\mathrm{H}_{2} \mathrm{O}_{2}$ and $\mathrm{NaOH}$, the organic compound formed is :
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}$
$\left(\mathrm{CH}_{3}\right)_{3} \mathrm{COH}$
$\mathrm{CH}_{3} \mathrm{CHOHCH}_{3}$
$\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}$
Correct Option: 1
Solution:
