Question:
In the given figure, if quadrilateral PQRS circumscribes a circle, then PD + QB =
(a) PQ
(b) QR
(c) PR
(d) PS
Solution:
We know that tangents drawn to a circle from the same external point will be equal in length.
Therefore,
PD = PA …… (1)
QB = QA …… (2)
Adding equations (1) and (2), we get,
PD + QB = PA + QA
By looking at the figure we can say,
PD + QB = PQ
Therefore option (a) is the correct answer.