Question:
In the given figure, find the area of the shaded region, where ABCD is a square of side 14 cm and all circles are of the same diameter.
Solution:
Area of the square $=\operatorname{Side}^{2}=14^{2}=196$ sq. $\mathrm{cm}$
Area of the circles $=4 \times \pi \times 3.5 \times 3.5=154$ sq. $\mathrm{cm}$
Area of the shaded region = Area of the square
$=196-154$
$=42 \mathrm{~cm}^{2}$