In the given figure, ∠B < ∠A and ∠C < ∠D. Show that AD > BC.

Given: ∠B < ∠A and ∠C < ∠D

To prove: AD > BC

Proof:

In $\Delta A O B$,

$\angle B<\angle A$

$\Rightarrow A O

In $\Delta C O D$,

$\angle C<\angle D$

$\Rightarrow O D

Adding (1) and (2), we get

$A O+O D

$\therefore A D