Question:
In the given figure, ABCD is a parallelogram in which ∠BDC = 45° and ∠BAD = 75°. Then, ∠CBD = ?
(a) 45°
(b) 55°
(c) 60°
(d) 75°
Solution:
(c) 60°
Explanation:
∠BAD = ∠BCD = 75o [Opposite angles are equal]
In ∆ BCD, ∠ C = 75o
∴ ∠CBD = 180o − (75o + 45o) = 60o