Question:
In the given circuit, the charge on $4 \mu \mathrm{F}$ capacitor will be :
Correct Option: , 4
Solution:
(4) $V_{1}+V_{2}=10$
and $4 V_{1}=6 V_{2}$
On solving above equations, we get
$V_{1}=6 \mathrm{~V}$
Charge on $4 \mu f$,
$q=C V_{1}=4 \times 6=24 \mu \mathrm{C}$
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