Question:
In the following digital circuit, what will be the output at 'Z', when the input (A,B) are $(1,0)$, $(0,0),(1,1),(0,1):$
Correct Option: , 3
Solution:
$Z=(\overline{P+R})$
$Z=(\overline{P+P Q})$
$Z=(\overline{P(1+Q)})$
$Z=(\bar{P})$ [Using Identity $(1+A)=1$ ]
$Z=\overline{(\overline{\mathrm{AB}})}$
$Z=\overline{\mathrm{AB}}$
Truth table for $\mathrm{Z}=\mathrm{AB}$
