Question:
In the adjoining figure, x:y:z = 5:4:6. If XOY is a straight line, find the values of x, y and z.
Solution:
Let $x=5 a, y=4 a$ and $z=6 a$
XOY is a straight line. Therefore,
$\angle X O P+\angle P O Q+\angle Y O Q=180^{\circ}$
$\Rightarrow 5 a+4 a+6 a=180^{\circ}$
$\Rightarrow 15 a=180^{\circ}$
$\Rightarrow a=12^{\circ}$
Therefore,
$x \Rightarrow 5 \times 12^{\circ}=60^{\circ}$
$y \Rightarrow 4 \times 12^{\circ}=48^{\circ}$
and $z \Rightarrow 6 \times 12^{\circ}=72^{\circ}$