Question:
In the adjoining figure, we have AC = DC and CB = CE. Show that AB = DE.
Solution:
Given, AC = DC …(i)
and C6 = CE …(ii)
According to Euclid’s axiom, if equals are added to equals, then wholes are also equal.
So, on adding Eqs.(i) and (ii), we get
AC + CB = DC + CE
=> AB = DE