Question:
In Q. No. 1, the probability that the digit is a multiple of 3 is
(a) $\frac{1}{3}$
(b) $\frac{2}{3}$
(c) $\frac{1}{9}$
(d) $\frac{2}{9}$
Solution:
GIVEN: digits are chosen from 1, 2, 3, 4, 5, 6, 7, 8, 9 are placed in a box and mixed thoroughly. One digit is picked at random.
TO FIND: Probability of getting a multiple of 3
Total number of digits is 9
Digits that are multiple of 3 are 3, 6 and 9
Total digits that are multiple of 3 are 3
We know that PROBABILITY = 
Hence probability of getting a multiple of 3 is 
Hence the correct option is option