In figure 9.39, AB ∥ DE. Find ∠ACD.
Since AB ∥ DE
∴ ∠ABC = ∠CDE = 40° [Alternate angles]
∴ ∠ACB = 180° − ∠ABC − ∠BAC
=180° − 40° − 30°
= 110°
∴ ∠ACD = 180° − 110° [Linear pair]
= 70°
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