Question:
In Fig. 17.29, BDEF and DCEF are each a parallelogram. Is it true that BD = DC? Why or why not?
Solution:
In parallelogram BDEF
$\therefore \mathrm{BD}=\mathrm{EF} \quad \ldots$ (i) (opposite sides of a parallelogram are equal)
In parallelogram DCEF
$\mathrm{CD}=\mathrm{EF} \quad \ldots$ (ii) $\quad$ (opposite sides of a parallelogram are equal)
From equations (i) and (ii)
$\mathrm{BD}=\mathrm{CD}$