Question:
In comparison to boron, berylium has :
Correct Option: 1
Solution:
In case of 'Be' electron remove from '2s' orbital while in case of 'B' electron remove from ' $2 p^{\prime}$ orbital. ' $2 s^{\prime}$ orbital have greater penetration effect then '2p' orbitals. So 'Be' having more I.E. then ' $B$ '
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