Question:
In Bohr's atomic model, the electron is assumed to revolve in a circular orbit of radius $0.5 A$. If the speed of electron is $2.2 \times 16^{6} \mathrm{~m} / \mathrm{s}$, then the current associated with the electron will be_______
$\times 10^{-2} \mathrm{~mA} .\left[\right.$ Take $\pi$ as $\left.\frac{22}{7}\right]$
Solution:
Sol. $\mathrm{I}=\frac{\mathrm{e}}{\mathrm{T}}=\frac{e \omega}{2 \pi}=\frac{\mathrm{eV}}{2 \pi}$
$I=\frac{1.6 \times 10^{-19} \times 2.2 \times 10^{6} \times 7}{2 \times 22 \times 0.5 \times 10^{-10}}$
$=1.12 \mathrm{~mA}$
$112 \times 10^{-2} \mathrm{~mA}$
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