Question:
In below fig. OP, OQ, OR and OS are four rays. Prove that: ∠POQ + ∠QOR + ∠SOR + ∠POS = 360°
Solution:
Given that
OP, OQ, OR and OS are four rays
You need to produce any of the ray OP, OQ, OR and OS backwards to a point in the figure.
Let us produce ray OQ backwards to a point T
So that TOQ is a line
Ray OP stands on the TOQ
Since ∠TOP, ∠POQ is a linear pair
∠TOP + ∠POQ = 180° ... (1)
Similarly,
Ray OS stands on the line TOQ
∠TOS + ∠SOQ = 180° ... (2)
But ∠SOQ = ∠SOR + ∠QOR ... (3)
So, eqn (2) becomes
∠TOS + ∠SOR + ∠OQR = 180°
Now, adding (1) and (3) you get ∠TOP + ∠POQ + ∠TOS + ∠SOR + ∠QOR = 360° ... (4)
∠TOP + ∠TOS = ∠POS
Eqn: (4) becomes
∠POQ + ∠QOR + ∠SOR + ∠POS = 360°