Question:
In an electrical circuit, a battery is connected to pass $20 \mathrm{C}$ of charge through it in a certain given time. The potential difference between two plates of the battery is maintained at $15 \mathrm{~V}$. The work done by the battery is
Solution:
Work done by battery $=Q(\Delta V)$
$\Rightarrow 20 \times 15=300 \mathrm{~J}$
$\therefore$ Ans. 300