In ∆ABC, AB = AC and ∠B = 50°.

In $\triangle A B C$, we have:

$A B=A C$

$\angle B=50^{\circ}$

Since $A B C$ is an isosceles triangle, we have:

$\angle C=\angle B$

$\angle C=50^{\circ}$

In triangle $\mathrm{ABC}$, we have:

$\angle A+\angle B+\angle C=180^{\circ}$

$\Rightarrow \angle A+50+50=180^{\circ}$

$\Rightarrow \angle A=180^{\circ}-100^{\circ}$

$\therefore \angle A=80^{\circ}$

Hence, the correct answer is option (c).