Question:
In a single throw of a die, the probability of getting a multiple of 3 is
(a) $\frac{1}{2}$
(b) $\frac{1}{3}$
(c) $\frac{1}{6}$
(d) $\frac{2}{3}$
Solution:
GIVEN: A dice is thrown once
TO FIND: Probability of getting a multiple of 3.
Total number on a dice is 6.
Numbers which are on multiple of 3 are 3 and 6
Total number of numbers which are multiple of 3 is 2
We know that PROBABILITY = 
Hence probability of getting a number which are multiple of 3 is equal to 
Hence the correct option is 