Question:
In a right-angled triangle, one of the acute angles measures 53°. Find the measure of each angle of the triangle.
Solution:
Let ABC be a triangle right-angled at B.
Then, $\angle B=90^{\circ}$ and let $\angle A=53^{\circ}$.
$\therefore \angle A+\angle B+\angle C=180^{\circ} \quad$ [Sum of the angles of a triangle]
$\Rightarrow 53^{\circ}+90^{\circ}+\angle C=180^{\circ}$
$\Rightarrow \angle C=37^{\circ}$
Hence, $\angle A=53^{\circ}, \angle B=90^{\circ}$ and $\angle C=37^{\circ}$.