In a frequency distribution,

Question:

In a frequency distribution, the mid value of a class is 10 and the width of the class is 6. The lower limit of the class is

(a) 6                      

(b) 7                    

(c) 8                          

(d) 12

Solution:

(b) Let x and y be the upper and lower class limit in a frequency distribution.

Now, mid value of a class  (x + y )/2=10  [given]

=> x + y = 20 …(i)

Also, given that, width of class  x- y = 6 …(ii)

On adding Eqs. (i) and (ii), we get

2x =20+ 6

=> 2x =26 => x = 13

On putting x = 13 in Eq. (i), we get

13+y = 20=> y = 7

Hence, the lower limit of the class is 7.

Leave a comment