Question.
In a cricket math, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.
In a cricket math, a batswoman hits a boundary 6 times out of 30 balls she plays. Find the probability that she did not hit a boundary.
Solution:
Number of times the batswoman hits a boundary = 6
Total number of balls played = 30
∴ Number of times that the batswoman does not hit a boundary = 30 − 6 = 24
$P($ she does not hit a boundary $)=\frac{\text { Number of times when she does not hit boundary }}{\text { Total number of balls played }}$
$=\frac{24}{30}=\frac{4}{5}$
Number of times the batswoman hits a boundary = 6
Total number of balls played = 30
∴ Number of times that the batswoman does not hit a boundary = 30 − 6 = 24
$P($ she does not hit a boundary $)=\frac{\text { Number of times when she does not hit boundary }}{\text { Total number of balls played }}$
$=\frac{24}{30}=\frac{4}{5}$