In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that:
Question:
In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. Find the probability that:
1. He hit a boundary
2. He did not hit a boundary.
Solution:
Number of times the batsman hits a boundary = 6
Total number of balls played = 30
Number of times the batsman did not hit a boundary = 30 - 6 = 24
1. Probability that the batsman hits a boundary
$=\frac{\text { Number of times hehita boundary }}{\text { Total no of balls }}$
= 6/30
= 15
2. Probability that the batsman does not hit a boundary
$=\frac{\text { Number of time he did not hita boundary }}{\text { Total no of balls }}$
= 24/30
= 4/5