Question:
In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. What is the probability that in a given delivery, the ball does not hit the boundary?
(a) $\frac{1}{4}$
(b) $\frac{1}{5}$
(C) $\frac{4}{5}$
(d) $\frac{3}{4}$
Solution:
(C) $\frac{4}{5}$
Explanation:
Total number of balls faced = 30
Number of times the ball hits the boundary = 6
Number of times the ball does not hit the boundary = (30 − 6 )= 24
Let E be the event that the ball does not hit the boundary. Then,
$P(E)=\frac{\text { Number of times ball does not hit the boundary }}{\text { Total number of balls }}=\frac{24}{30}=\frac{4}{5}$
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