Question:
In a binary compound, atoms of element $\mathrm{A}$
form a hcp structure and those of element $\mathrm{M}$
occupy $2 / 3$ of the tetrahedral voids of the hep structure. The formula of the binary compound is:
Correct Option: , 2
Solution:
$\mathrm{M}_{12 \times \frac{2}{3}} \mathrm{~A}_{6}$
$\mathrm{M}_{8} \mathrm{~A}_{6}$
$\mathrm{M}_{4} \mathrm{~A}_{3}$