Question:
In a ∆ABC, if c2 + a2 – b2 = ac, then the measure of angle B is ____________.
Solution:
In a ∆ABC,
if c2 + a2 − b2 = ac
Since $\cos B=\frac{c^{2}+a^{2}-b^{2}}{2 a c}$
$=\frac{a c}{2 a c}$
i.e $\cos B=\frac{1}{2}$
i.e $B=\frac{\pi}{3}$
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