Question: 
hybridization of carbon $1,2,3$ and 4 respectively are :
$\mathrm{sp}^{3}, \mathrm{sp}, \mathrm{sp}^{3}, \mathrm{sp}^{3}$
$\mathrm{sp}^{2}, \mathrm{sp}^{2}, \mathrm{sp}^{2}, \mathrm{sp}^{3}$
$\mathrm{sp}^{2}, \mathrm{sp}, \mathrm{sp}^{2}, \mathrm{sp}^{3}$
$\mathrm{sp}^{2}, \mathrm{sp}^{3}, \mathrm{sp}^{2}, \mathrm{sp}^{3}$
Correct Option: , 3
Solution:
$\left[\stackrel{1}{\mathrm{C}} \mathrm{H}_{2}=\stackrel{2}{\mathrm{C}}=\stackrel{3}{\mathrm{C}} \mathrm{H}-\stackrel{4}{\mathrm{C}} \mathrm{H}_{3}\right]$
