If x / y is the additive inverse of

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Question:
If $x / y$ is the additive inverse of $c / d$, then, $(x / y)-(c / d)=0$

Solution:

False.

Let $x / y=2 / 3$ and its additive inverse $c / d=-2 / 3$

Then, $(x / y)-(c / d)$

$=(2 / 3)-(-2 / 3)$

$=(2 / 3)+(2 / 3)$

$=4 / 3$