If x is a positive integer such that the distance between points

It is given that distance between $P(x, 2)$ and $Q(3,-6)$ is 10 .

In general, the distance between $\mathrm{A}\left(x_{1}, y_{1}\right)$ and $\mathrm{B}\left(x_{2}, y_{2}\right)$ is given by,

$\mathrm{AB}^{2}=\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}$

So,

$10^{2}=(x-3)^{2}+(2+6)^{2}$

On further simplification,

$(x-3)^{2}=36$

$x=3 \pm 6$

$=9,-3$

We will neglect the negative value. So,

$x=9$

So the answer is (c)