If $x$ and $y$ are integers such that $x^{2}>y^{2}$, then $x^{3}>y^{3}$.
False
Suppose, $-1$ and $-2$ are integers
Then, $(-2)^{2^{\prime}}>(-1)^{2}=4>1$
and $(-2)^{3}<(-1)^{3}=-8<-1$
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