Question:
If the velocity-time graph has the shape $\mathrm{AMB}$, what would be the shape of the corresponding acceleration-time graph?
(1)
(2)
(3)
(4)
Correct Option: 1
Solution:
$a=\frac{d v}{d t}=$ slope of $(v-t)$ curve
If $m=+$ ve, then equation of straight line isc
$y=m x+c \Rightarrow v=m t+c$
(for MB)
If $m=-$ ve, then equation of straight line is
$y=-m x+c \Rightarrow v=-m t+c($ for $A M)$
If we differentiate equation (1) and (2), we get
$\mathrm{a}_{\mathrm{MB}}=+\mathrm{ve}=\mathrm{m}$
$a_{A M}=-v e=-m$, so graph of $(a-t)$ will be
