Question:
If the system of linear equations
$x-2 y+k z=1$
$2 x+y+z=2$
$3 x-y-k z=3$
has a solution $(x, y, z), z \neq 0$, then $(x, y)$ lies on the straight line whose equation is :
Correct Option: , 3
Solution:
x – 2y + kz = 1 ...(1)
2x + y + z = 2 ...(2)
3x – y – kz = 3 ...(3)
(1) +(3)
$\Rightarrow 4 x-3 y=4$