Question:
If the sum of the roots of a quadratic equation is 6 and their product is 6, the equation is
(a) $x^{2}-6 x+6=0$
(b) $x^{2}+6 x-6=0$
(c) $x^{2}-6 x-6=0$
(d) $x^{2}+6 x+6=0$
Solution:
(a) $x^{2}-6 x+6=0$
Given :
Sum of roots $=6$
Product of roots $=6$
Thus, the equation is:
$x^{2}-6 x+6=0$