Question:
If the solubility product of CuS is 6 × 10−16, calculate the maximum molarity of CuS in aqueous solution.
Solution:
Solubility product of CuS, Ksp = 6 × 10−16
Let s be the solubility of CuS in mol L−1.
Now,
= s × s
= s2
Then, we have, $K_{\mathrm{sp}}=s^{2}=6 \times 10^{-16}$
$\Rightarrow s=\sqrt{6 \times 10^{-16}}$
= 2.45 × 10−8 mol L−1
Hence, the maximum molarity of CuS in an aqueous solution is 2.45 × 10−8 mol L−1.