If the radius of a sphere is doubled,

Question:

If the radius of a sphere is doubled, what is the ratio of the volume of the first sphere to that of the second sphere?

Solution:

Let v1 and v2 be the volumes of the first and second sphere respectively

Radius of the first sphere = r

Radius of the second sphere = 2r

Therefore, $\frac{\text { Volume of first sphere }}{\text { Volume of second sphere }}=\frac{\frac{4}{3} \pi r^{3}}{\frac{4}{3} \pi(2 r)^{3}}$

= 1/8

 

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