Question:
If the probability of winning a game is 0.4, the probability of losing it is
(a) 0.96
(b) $\frac{1}{0.4}$
(c) 0.6
(d) none of these
Solution:
(c) 0.6
Explanation:
Let E be the event of winning a game.
Then, ( not E) is the event of not winning the game or of losing the game.
Then, P(E) = 0.4
Now, P(E) + P(not E) = 1
⇒ 0.4 + P(not E) = 1
⇒ P(not E) = 1− 0.4 = 0.6
∴ P(losing the game) = P(not E) = 0.6