Question:
If the prime factorization of a natural number n is 23 ✕ 32 ✕ 52 ✕ 7, write the number of consecutive zeros in n.
Solution:
Since, it is given that
$n=2^{3} \times 3^{2} \times 5^{2} \times 7$
$n=8 \times 9 \times 25 \times 7$
n=(7 \times 9 \times 2) \times(4 \times 25)
$n=(7 \times 9 \times 2) \times 100$
$n=(7 \times 9 \times 2) \times 100$
$n=12600$
Hence the number of consecutive zeroes are2