Question:
If the points(x, 4) lies on a circle whose centre is at the origin and radius is 5, then x =
(a) ±5
(b) ±3
(c) 0
(d) ±4
Solution:
It is given that the point A(x, 4) is at a distance of 5 units from origin O.
So, apply the distance formula to get,
$5^{2}=(x)^{2}+4^{2}$
Therefore,
$x^{2}=9$
So,
$x=\pm 3$
So the answer is (b)