If the lateral surface of a cylinder is 94.2 cm2

Question:

If the lateral surface of a cylinder is $94.2 \mathrm{~cm}^{2}$ and its height is $5 \mathrm{~cm}$, find:

(i) radius of its base

(ii) volume of the cylinder [Use pi = 3.141]

 

Solution:

(i) Given,

Height of the cylinder = 5 cm

Let radius of cylinder be 'r'

Curved surface of the cylinder $=94.2 \mathrm{~cm}^{2}$

$2 \pi \mathrm{rh}=94.2 \mathrm{~cm}^{2}$

$r=3 \mathrm{~cm} \quad[\pi=31.4, h=5 \mathrm{~cm}]$

(ii) Volume of the cylinder $=\pi r^{2} h=\left(3.14 \times 3^{2} \times 5\right) \mathrm{cm}^{3}=141.3 \mathrm{~cm}^{3}$

 

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