If the difference between the circumference and radius of a circle is 37 cm, then its area is
(a) $154 \mathrm{~cm}^{2}$
(b) $160 \mathrm{~cm}^{2}$
(c) $200 \mathrm{~cm}^{2}$
(d) $150 \mathrm{~cm}^{2}$
We have given the difference between circumference and radius of the circle.
Let C be the circumference, r be the radius and A be the area of the circle.
Therefore, from the given condition we have
$C-r=2 \pi r-r$
$\therefore 37=2 \pi r-r$
$\therefore 37=r(2 \pi-1)$
$\therefore r=\frac{37}{(2 \pi-1)}$
Now we will substitute $\pi=\frac{22}{7}$.
$\therefore r=\frac{37}{\left(2 \times \frac{22}{7}-1\right)}$
$\therefore r=\frac{37}{\left(\frac{44}{7}-1\right)}$
$\therefore r=\frac{37}{\left(\frac{44-7}{7}\right)}$
$\therefore r=\frac{37}{\left(\frac{37}{7}\right)}$
$\therefore r=37 \times \frac{7}{37}$
$\therefore r=7$
Now we will substitute the value of $r$ in $A=\pi r^{2}$.
$\therefore A=\pi \times 7^{2}$
Now we will substitute $\pi=\frac{22}{7}$.
$\therefore A=\frac{22}{7} \times 7^{2}$
$\therefore A=22 \times 7$
$\therefore A=154$
Therefore, area of the circle is $154 \mathrm{~cm}^{2}$.
Hence, the correct answer is option (a).