Question:
If the centroid of the triangle formed by (7, x) (y, −6) and (9, 10) is at (6, 3), then (x, y) =
(a) (4, 5)
(b) (5, 4)
(c) (−5, −2)
(d) (5, 2)
Solution:
We have to find the unknown co-ordinates.
The co-ordinates of vertices are $\mathrm{A}(7, x) ; \mathrm{B}(y,-6) ; \mathrm{C}(9,10)$
The co-ordinate of the centroid is (6, 3)
We know that the co-ordinates of the centroid of a triangle whose vertices are $\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right),\left(x_{3}, y_{3}\right)$ is
$\left(\frac{x_{1}+x_{2}+x_{3}}{3}, \frac{y_{1}+y_{2}+y_{3}}{3}\right)$
So,
$(6,3)=\left(\frac{y+7+9}{3}, \frac{x-6+10}{3}\right)$
Compare individual terms on both the sides-
$\frac{x+4}{3}=3$
So,
$x=5$
Similarly,
$\frac{y+16}{3}=6$
So,
$y=2$
So the answer is (d)