If the angle of elevation of a cloud from a point 200 m above a lake is 30°

Let  be the surface of the lake and  be the point of observation. So  m.

The given situation can be represented as,

Here, is the position of the cloud and  is the reflection in the lake. Then .

Let $P M$ be the perpendicular from $P$ on $C B$. Then $\angle C P M=30^{\circ}$ and $\angle C^{\top} P M=60^{\circ}$.

Let $C M=h, P M=x$, then $C B=h+200$ and $C^{\prime} B=h+200$

Here, we have to find the height of cloud.

So we use trigonometric ratios.

In ,

$\Rightarrow \tan 30^{\circ}=\frac{C M}{P M}$

$\Rightarrow \frac{1}{\sqrt{3}}=\frac{h}{x}$

$\Rightarrow x=\sqrt{3} h$

Again in $\triangle P M C^{\prime}$,

$\Rightarrow \tan 60^{\prime}=\frac{C^{\prime} M}{P M}$

$\Rightarrow \sqrt{3}=\frac{C^{\prime} B+B M}{P M}$

$\Rightarrow \sqrt{3}=\frac{h+200+200}{x}$

$\Rightarrow \sqrt{3} x=h+400$

Put $x=\sqrt{3} h$

$\Rightarrow 3 h=h+400$

$\Rightarrow 2 h=400$

$\Rightarrow h=200$

Now,

$\Rightarrow C B=h+200$

$\Rightarrow C B=200+200$

$\Rightarrow C B=400$

Hence the correct answer is d.