Question: If the angle between the line $x=\frac{y-1}{2}=\frac{z-3}{\lambda}$ and the plane $x+2 y+3 z=4$ is $\cos ^{-1}\left(\sqrt{\frac{5}{14}}\right)$, then $\lambda$ equals:-
$\frac{2}{5}$
$\frac{5}{3}$
$\frac{2}{3}$
$\frac{3}{2}$
Correct Option:
Solution: