If sum of the number 985 and two other numbers obtained by arranging the digits of 985 in cyclic order is divided by 111, 22 and 37 respectively.
Question:
If sum of the number 985 and two other numbers obtained by arranging the digits of 985 in cyclic order is divided by 111, 22 and 37 respectively. Find the quotient in each case.
Solution:
The sum of $(985+859+598)$ when divided by :
(i) 111
$Q$ uotient $=(9+8+5)=22$
(ii) 22 , i. e, $(9+8+5)$
$Q$ uotient $=111$
(iii) $37\left(=\frac{111}{3}\right)$
$Q$ uotient $=3(9+8+5)=66$