Question:
If speed $\mathrm{V}$, area $\mathrm{A}$ and force $\mathrm{F}$ are chosen as fundamental units, then the dimension of Young's modulus will be :
Correct Option: , 4
Solution:
(4) Young's modulus, $Y=\frac{\text { stress }}{\text { strain }}$
$\Rightarrow Y=\frac{\mathrm{F}}{\mathrm{A}} / \frac{\Delta \ell}{\ell_{0}}=\mathrm{FA}^{-1} \mathrm{~V}^{0}$
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