Question:
If $R$ is a relation from $A=\{11,12,13\}$ to $B=\{8,1012\}$ defined by $y=x-3$, then $R^{-1}=$
Solution:
Given: $R=\{(x, y): y=x-3, x \in A$ and $y \in B\}$, where $A=\{11,12,13\}$ and $B=\{8,1012\}$.
R = {(11, 8), (13, 10)}
Therefore, $R^{-1}=\{(8,11),(10,13)\}$
Hence, $R^{-1}=\{(\underline{8}, 11),(\underline{10}, 13)\}$.