Question.
If $\left(x^{51}+51\right)$ is divided by $(x+1)$ then the remainder is
(a) 0
(b) 1
(c) 49
(d) 50
If $\left(x^{51}+51\right)$ is divided by $(x+1)$ then the remainder is
(a) 0
(b) 1
(c) 49
(d) 50
Solution:
Let $f(x)=x^{51}+51$
By remainder theorem, when f(x) is divided by (x + 1), then the remainder = f(−1).
Putting x = −1 in f(x), we get
$f(-1)=(-1)^{51}+51=-1+51=50$
∴ Remainder = 50
Thus, the remainder when $\left(x^{51}+51\right)$ is divided by $(x+1)$ is 50
Hence, the correct answer is option (d).
Let $f(x)=x^{51}+51$
By remainder theorem, when f(x) is divided by (x + 1), then the remainder = f(−1).
Putting x = −1 in f(x), we get
$f(-1)=(-1)^{51}+51=-1+51=50$
∴ Remainder = 50
Thus, the remainder when $\left(x^{51}+51\right)$ is divided by $(x+1)$ is 50
Hence, the correct answer is option (d).