If force $(\mathrm{F})$, length (L) and time $(\mathrm{T})$ are taken as the fundamental quantities. Then what will be the dimension of density :
Correct Option: 1
Density $=\left[F^{\mathrm{a}} \mathrm{L}^{\mathrm{b}} \mathrm{T}^{\mathrm{c}}\right]$
${\left[\mathrm{ML}^{-3}\right]=\left[\mathrm{M}^{\mathrm{a}} \mathrm{L}^{\mathrm{a}} \mathrm{T}^{-2 \mathrm{a}} \mathrm{L}^{\mathrm{b}} \mathrm{T}^{\mathrm{c}}\right] }$
${\left[\mathrm{M}^{\mathrm{l}} \mathrm{L}^{-3}\right]=\left[\mathrm{M}^{\mathrm{a}} \mathrm{L}^{\mathrm{a}+\mathrm{b}} \mathrm{T}^{-2 \mathrm{a}+\mathrm{c}}\right] }$
$\mathrm{a}=1 \quad ; \quad \mathrm{a}+\mathrm{b}=-3 \quad ; \quad-2 \mathrm{a}+\mathrm{c}=0$
$\begin{array}{ll}1+b=-3 & c=2 a \\ b=-4 & c=2\end{array}$
So, density $=\left[F^{1} L^{-4} T^{2}\right]$