Question:
If ' $C^{\prime}$ and ' $\mathrm{V}$ ' represent capacity and voltage respectively then what are the dimensions of $\lambda$ where $C / V=\lambda$ ?
Correct Option: 1,
Solution:
(1)
$\because v=\frac{w}{q}$ and $c=\frac{q}{v}$
dimension of $\frac{c}{v}$
$\Longrightarrow \frac{q}{v^{2}}$
$\Rightarrow \frac{q}{w^{2}} \times q^{2} \Rightarrow \frac{q^{3}}{w^{2}}$
$\Rightarrow \frac{\mathrm{I}^{3} \mathrm{~T}^{3}}{\mathrm{M}^{2} \mathrm{~L}^{4} \mathrm{~T}^{-4}} \Rightarrow\left[\mathrm{M}^{-2} \mathrm{~L}^{-4} \mathrm{~T}^{7} \mathrm{I}^{3}\right]$
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