Question:
If AOB is a diameter of a circle and C is a point on the circle, then AC2+ BC2 = AB2.
Solution:
True
Since, any diameter of the circle subtends a right angle to any point on the circle.
If AOB is a diameter of a circle and C is a point on the circle, then ΔACB is right angled at C. In right angled ΔACB, [use Pythagoras theorem]
AC2 + BC2 = AB2
