Question:
If a two digit number is chosen at random, then the probability that the number chosen is a multiple of 3, is
(a) $\frac{3}{10}$
(b) $\frac{29}{100}$
(c) $\frac{1}{3}$
(d) $\frac{7}{25}$
Solution:
GIVEN: A two digit number is chosen at random
TO FIND: Probability that the number chosen is a multiple of 3
Total two digit numbers is 90
Two digit Numbers multiple of 3 are 12,15,18,21,24,27,30,33,36,39,42,45,48,51,54,57,60,63,66,69,72,75,78,81,84,87,90,93,96,99
Hence total two digit numbers multiple of 3 are 30
We know that PROBABILITY = 
Hence probability that the number chosen is a multiple of 3 is equal to 
Hence the correct option is